Exponent Rules: Product, Quotient and Power
An exponent is a short way to write the same number multiplied again and again. A few rules help you work with exponents quickly.
What you'll be able to do
- Multiply and divide powers that have the same base.
- Raise a power, or a product, to a power.
- Change a base to match another, like 4³ = 2⁶.
- Find a missing exponent.
- Spot common mistakes with signs and bases.
The big idea
2⁵ is a short way to write 2 × 2 × 2 × 2 × 2. The 2 is called the base. The small raised 5 is the exponent. It tells you how many 2s to multiply.
Multiplying. Look at 2³ × 2⁴. That is three 2s times four more 2s. Count them all: 3 + 4 = 7. So 2³ × 2⁴ = 2⁷. When the bases match, you add the exponents.
Dividing. Look at 2⁶ ÷ 2². Write six 2s on top and two 2s on the bottom. Each 2 on the bottom cancels a 2 on top. That leaves 6 − 2 = 4 of them. So 2⁶ ÷ 2² = 2⁴. When the bases match, you subtract the exponents.
Power of a power. Look at (2²)³. It means 2² × 2² × 2². Add the exponents: 2 + 2 + 2 = 6. That is the same as 2 × 3. So (2²)³ = 2⁶. You multiply the exponents.
More than one letter. Work on the numbers first. Then work on each letter on its own. For example, (3x⁴y)(5x²y³) = 15x⁶y⁴. A power outside parentheses goes to every part inside. So (2x³)² = 4x⁶, because the 2 gets squared too.
Watch the signs. An exponent covers only what it touches. So −3² = −9, but (−3)² = 9.
Changing the base. The rules need matching bases. 4 is 2², so 4³ = (2²)³ = 2⁶. Now 4³ × 2⁵ = 2⁶ × 2⁵ = 2¹¹.
Finding a missing exponent. If 2^n = 2⁷, then n = 7. Make the bases match, then compare the exponents.
Adding powers is different. The rules work for multiplying and dividing, not adding. 2⁵ + 2⁵ is two copies of 2⁵. That is 2 × 2⁵ = 2⁶, not 2¹⁰.
Words you need
- Base
- The number or letter being multiplied. In 5³, the base is 5.
- Exponent
- The small raised number. In 5³, the exponent is 3. It says to multiply three 5s.
- Power
- A base with an exponent, like 5³. You say it as "5 to the third power."
- Coefficient
- The number in front of a letter. In 4x², the coefficient is 4.
- Simplify
- Write something in its shortest form. x³ · x⁴ simplifies to x⁷.
- Product and quotient
- A product is the answer to a times problem. A quotient is the answer to a divide problem.
- Square root and cube root
- The square root of 9 is 3, because 3 × 3 = 9. The cube root of 8 is 2, because 2 × 2 × 2 = 8.
The rules
| When you... | Do this | Example |
|---|---|---|
| Multiply powers with the same base | Add the exponents | x³ · x⁴ = x⁷ |
| Divide powers with the same base | Subtract the exponents | x⁶ ÷ x² = x⁴ |
| Raise a power to a power | Multiply the exponents | (x²)³ = x⁶ |
| Raise a product to a power | Raise every part | (2x³)² = 4x⁶ |
| Have different bases | Rewrite them to match | 4³ = 2⁶ |
Worked examples
Example 1
Simplify (2x³y)(4x²y⁵).
- Multiply the numbers: 2 × 4 = 8.
- Add the exponents on x: 3 + 2 = 5.
- y by itself means y¹. Add the exponents on y: 1 + 5 = 6.
- So the answer is 8x⁵y⁶.
Answer: 8x⁵y⁶
Example 2
Simplify (3a²b)³.
- The power 3 goes to every part inside the parentheses.
- The 3 gets cubed: 3 × 3 × 3 = 27.
- For a², multiply the exponents: 2 × 3 = 6. For b, it is 1 × 3 = 3.
- So the answer is 27a⁶b³.
Answer: 27a⁶b³
Example 3
Write 8² × 2³ as one power of 2.
- 8 is 2³, so 8² = (2³)².
- Multiply the exponents: 3 × 2 = 6. So 8² = 2⁶.
- Now the bases match: 2⁶ × 2³ = 2⁹.
Answer: 2⁹ = 512
Common mistakes
Multiplying the exponents when you multiply powers: x³ · x⁴ = x¹². Add them instead. x³ · x⁴ = x⁷. You multiply exponents only for a power of a power.
Multiplying the bases: 2³ × 2⁴ = 4⁷. The base stays the same. You are still multiplying 2s. The answer is 2⁷.
Forgetting the number inside the parentheses: (2x³)² = 2x⁶. The 2 gets squared too. 2² = 4, so (2x³)² = 4x⁶.
Reading −3² as 9. The exponent covers only the 3. So −3² = −9. Only (−3)² = 9.
Practice: 20 questions
5 of 20 are word problems. For a word problem, sketch it first and mark what you know.
Tier 1 Foundations Use the rule directly
- Simplify (3x⁴y)(5x²y³).
- Simplify (2a³b²)⁴.
- Simplify 20m⁹n⁴ ÷ (5m³n).
- A kilometer is 10³ meters. A meter is 10² centimeters. A centimeter is 10 millimeters. How many millimeters are in 10⁴ kilometers? Write your answer as a power of 10. Word problem
- Sam says 2³ × 2⁴ = 4⁷. Find his mistake. What is the correct answer?
Tier 2 Intermediate One more step to think through
- Simplify (4x³y²)³ ÷ (8x⁵y).
- Simplify −3x² · (−3x)².
- Which is greater, −2⁴ or (−2)⁴?
- A square tile is 3a²b units long on each side. What is the total area of 12 of these tiles? Word problem
- A box holds 4³ bags. Each bag holds 2⁵ marbles. How many marbles are in the box? Write your answer as one power of 2. Word problem
Tier 3 Advanced Several steps - find the hidden structure
- Simplify (2a³b)⁴ · (3ab²)² ÷ (6a⁵b³).
- (3xᵏy²)³ ÷ (9x⁴y) = 3x¹¹y⁵. What is k?
- A colony starts with 81 bacteria. The number triples every hour. After how many hours will there be 3¹⁰ bacteria? Word problem
- A data center has 2⁴ server cabinets. Each cabinet holds 4³ hard drives, and each drive stores 8² gigabytes. What is the total storage of the data center, written as a single power of 2? Word problem
- Jun says 3⁴ · 9² = 27⁶. Find his mistake. What is the correct answer, as a power of 3?
Tier 4 Challenge Stretch problems, some above grade level
- Put 2³⁰⁰, 3²⁰⁰ and 5¹⁰⁰ in order from least to greatest. Do it without working them out.
- How many times as great as (3²)³ is 3 raised to the power 2³?
- Find the value of (2¹⁰⁰ − 2⁹⁹) ÷ 2⁹⁸.
- Solve 3ˣ⁺² + 3ˣ = 90.
- Raising a number to the power 1/3 takes its cube root. For example, 8^(1/3) = 2, because 2 × 2 × 2 = 8. Simplify (27x⁶y⁹)^(2/3). Above grade level
Answers
Tier 1 Foundations
- 15x⁶y⁴. Multiply the numbers: 3 × 5 = 15. Add the exponents. x: 4 + 2 = 6. y: 1 + 3 = 4. So (3x⁴y) · (5x²y³) = 15x⁶y⁴.
- 16a¹²b⁸. The power 4 applies to every part of (2a³b²)⁴: 2⁴ = 16, a: 3 × 4 = 12, b: 2 × 4 = 8. So (2a³b²)⁴ = 16a¹²b⁸.
- 4m⁶n³. Numbers: 20 ÷ 5 = 4. Add the exponents you multiply and subtract the ones you divide. m: 9 − 3 = 6. n: 4 − 1 = 3. So 20m⁹n⁴ ÷ (5m³n) = 4m⁶n³.
- 10¹⁰ = 10,000,000,000. 10 by itself means 10¹. Add the exponents: 3 + 2 + 1 + 4 = 10. So 10³ × 10² × 10 × 10⁴ = 10¹⁰ = 10,000,000,000.
- 2⁷ = 128. Sam multiplied the bases. The base should stay 2. Add the exponents: 3 + 4 = 7. So 2³ × 2⁴ = 2⁷ = 128.
Tier 2 Intermediate
- 8x⁴y⁵. The power 3 applies to every part of (4x³y²)³: 4³ = 64, x: 3 × 3 = 9, y: 2 × 3 = 6. So (4x³y²)³ = 64x⁹y⁶. Numbers: 64 ÷ 8 = 8. Add the exponents you multiply and subtract the ones you divide. x: 9 − 5 = 4. y: 6 − 1 = 5. So (4x³y²)³ ÷ (8x⁵y) = 8x⁴y⁵.
- −27x⁴. The power 2 applies to every part of (−3x)²: (−3)² = 9, x: 1 × 2 = 2. So (−3x)² = 9x². Multiply the numbers: (−3) × 9 = −27. Add the exponents. x: 2 + 2 = 4. So −3x² · (−3x)² = −27x⁴.
- (−2)⁴ is greater. (−2)⁴ = 16, and −2⁴ = −16.
- 108a⁴b². The power 2 applies to every part of (3a²b)²: 3² = 9, a: 2 × 2 = 4, b: 1 × 2 = 2. So (3a²b)² = 9a⁴b². Multiply the numbers: 12 × 9 = 108. So 12 · (3a²b)² = 108a⁴b².
- 2¹¹ = 2,048. Write every power with base 2. 4³ = (2²)³ = 2⁶. Now the bases match: 6 + 5 = 11. So 4³ × 2⁵ = 2¹¹ = 2,048.
Tier 3 Advanced
- 24a⁹b⁵. The power 4 applies to every part of (2a³b)⁴: 2⁴ = 16, a: 3 × 4 = 12, b: 1 × 4 = 4. So (2a³b)⁴ = 16a¹²b⁴. The power 2 applies to every part of (3ab²)²: 3² = 9, a: 1 × 2 = 2, b: 2 × 2 = 4. So (3ab²)² = 9a²b⁴. Numbers: (16 × 9) ÷ 6 = 24. Add the exponents you multiply and subtract the ones you divide. a: 12 + 2 − 5 = 9. b: 4 + 4 − 3 = 5. So (2a³b)⁴ · (3ab²)² ÷ (6a⁵b³) = 24a⁹b⁵.
- k = 5. Look at the x exponents only. Cubing xᵏ gives x³ᵏ. Dividing by x⁴ gives x³ᵏ⁻⁴. So 3k − 4 = 11, and k = 5.
- n = 6. After n hours there are 81 · 3ⁿ bacteria. 81 = 3⁴, so 3⁴ · 3ⁿ = 3¹⁰. That means 4 + n = 10, so n = 6. Check n = 6: left side 59,049, right side 59,049.
- 2¹⁶ = 65,536. Write every power with base 2. 4³ = (2²)³ = 2⁶. 8² = (2³)² = 2⁶. Now the bases match: 4 + 6 + 6 = 16. So 2⁴ × 4³ × 8² = 2¹⁶ = 65,536.
- 3⁸ = 6,561. Jun multiplied the bases and added the exponents. The bases don't match yet. Write every power with base 3. 9² = (3²)² = 3⁴. Now the bases match: 4 + 4 = 8. So 3⁴ × 9² = 3⁸ = 6,561.
Tier 4 Challenge
- 5¹⁰⁰ < 2³⁰⁰ < 3²⁰⁰. Give them all the exponent 100. 2³⁰⁰ = (2³)¹⁰⁰ = 8¹⁰⁰, and 3²⁰⁰ = (3²)¹⁰⁰ = 9¹⁰⁰. With the same exponent, the bigger base wins: 5 < 8 < 9. Checked by computing every value exactly.
- 9. 2³ = 8, so the second number is 3⁸. (3²)³ = 3⁶. And 3⁸ ÷ 3⁶ = 3² = 9.
- 2. 2¹⁰⁰ is 2 × 2⁹⁹, so 2¹⁰⁰ − 2⁹⁹ is just one 2⁹⁹. Then 2⁹⁹ ÷ 2⁹⁸ = 2.
- x = 2. 3ˣ⁺² is 9 · 3ˣ. So the left side is 9 · 3ˣ + 3ˣ = 10 · 3ˣ. Then 10 · 3ˣ = 90 gives 3ˣ = 9, so x = 2. Check x = 2: left side 90, right side 90.
- 9x⁴y⁶. The power 2/3 applies to every part of (27x⁶y⁹)^(2/3): 27^(2/3) = 9, x: 6 × 2/3 = 4, y: 9 × 2/3 = 6. So (27x⁶y⁹)^(2/3) = 9x⁴y⁶.
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